In a compound C , H and N are present in 9 : 1 : 3 . 5 by weight. If molecular weight of compound is 108 , the molecular formula of compound is

Step-by-step solution

Element Ratio (by weight) Atomic weight Mol Ratio Simplest Mol Ratio C 9 12 9 12 = 0 . 75 0 . 75 0 . 25 = 3 H 1 1 1 1 = 1 . 00 1 . 00 0 . 25 = 4 N 3 . 5 14 3 . 5 14 = 0 . 25 0 . 25 0 . 25 = 1 ∴ Empirical formula = C 3 H 4   N The empirical formula mass = 3 × 12 + 4 × 1 + 14 = 54   g Given, molecular mass = 108   g Thus, n = 108 54 = 2 Hence, molecular formula = (Empirical formula) × 2 C 3 H 4   N × 2 = C 6 H 8   N 2