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BITSAT Some Basic Concepts of Chemistry PYQs with Solutions

24 previous year questions from Some Basic Concepts of Chemistry (BITSAT Chemistry) with answers and solutions. Numbered list, year tags, and one-tap solutions — built for serious JEE / NEET practice.

24 questionsChemistry2009–2024Answers + solutions

About Some Basic Concepts of Chemistry PYQs

Some Basic Concepts of Chemistry has 24 previous year questions in the Quantrex Academy BITSAT Chemistry bank. The 24 questions in this list come from BITSAT (24), spanning 2009 to 2024. Each question opens on its own page with the options, the correct answer and the worked solution where available.

Questions by year (this list)

2024: 2
2022: 1
2020: 3
2019: 1
2018: 1
2017: 3
2016: 4
2014: 2
2013: 2
2012: 2
2011: 1
2010: 1

Some Basic Concepts of Chemistry questions with solutions

1 L closed flask contains a mixture of 4 g of methane and 4.4 g of carbon dioxide. The pressure inside the flask at 27^ ^ ∘ C is [Assume ideal behaviour of gases]

BITSAT 2024 Solution View → 2

In which mode of expression, the concentration of a solution remains independent of temperature?

BITSAT 2024 Solution View → 3

A certain metal sulphide, M S_2 , is used extensively as a high temperature lubricant. If MS_2 is 40.06 \% by mass sulphur, metal M has atomic mass.

BITSAT 2022 Solution View → 4

If 0.2 gram of an organic compound containing carbon, hydrogen and oxygen on combustion, yielded 0.147 gram carbon dioxide and 0.12 gram water. What will be the content of oxygen

BITSAT 2020 Solution View → 5

An ideal gaseous mixture of ethane (C_ 2 H_ 6 ) and ethene (C_ 2 H_ 4 ) occupies 28 litre at 1 atm and 273 ~K . The mixture reacts completely with 128 ~gO_ 2 to produce CO_ 2 and

BITSAT 2020 Solution View → 6

The amount of H_ 2 O_ 2 present in 1 litre of 1.5 N H_ 2 O_ 2 solution, is:

BITSAT 2020 Solution View → 7

In a compound C, H and N are present in 9: 1: 3. 5 by weight. If molecular weight of compound is 108 , the molecular formula of compound is

BITSAT 2019 Solution View → 8

The empirical formula and molecular mass of a compound are CH _ 2 O and 180g respectively. The molecular formula of the compound will be

BITSAT 2018 Solution View → 9

On electrolysis of water, a total of 1mole of gases is evolved. The amount of water decomposed is

BITSAT 2017 Solution View → 10

0. 765g of an acid gives 0. 535g of CO _ 2 and 0. 138g of H _ 2 O . Then, the ratio of percentage of carbon and hydrogen is&

BITSAT 2017 Solution View → 11

Which of the following has the largest& number of moles?

BITSAT 2017 Solution View → 12

The normality of 26 \% (wt/vol) solution of ammonia (density =0.855 ) is approximately:

BITSAT 2016 Solution View → 13

1.25 g of a sample of Na_ 2 CO_ 3 and Na_ 2 SO_ 4 is dissolved in 250 ml solution. 25 ml of this solution neutralises 20 ml of 0.1 N H_ 2 SO_ 4 . The \% of Na_ 2 CO_ 3 in this

BITSAT 2016 Solution View → 14

Formation of polyethylene from calcium carbide takes place as follows array l CaC_ 2 +2 H_ 2 O Ca(OH)_ 2 +C_ 2 H_ 2 C_ 2 H_ 2 +H_ 2 C_ 2 H_ 4 nC_ 2 H_ 4 (-CH_ 2 -CH_ 2 -)_ n array

BITSAT 2016 Solution View → 15

A compound of Xe and F is found to have 53.5 \% of Xe. What is oxidation number of Xe in this compound?

BITSAT 2016 Solution View → 16

The formation of CO and CO_ 2 illustrates the law of

BITSAT 2014 Solution View → 17

3.92 g of ferrous ammonium sulphate react completely with 50 ml N 10 KMnO_ 4 solution. The percentage purity of the sample is

BITSAT 2014 Solution View → 18

How many grams of concentrated nitric acid solution should be used to prepare 250 mL of 2.0 MHNO_ 3 ? The concentrated acid is 70 \% HNO_ 3

BITSAT 2013 Solution View → 19

Equal weights of NaCl and KCl are dissolved separately in equal volumes of solutions. Molarity of the two solutions will be :

BITSAT 2013 Solution View → 20

Number of atoms of He in 100 amu of He(atomic wt. of He is 4) are:

BITSAT 2012 Solution View → 21

In the reaction of KMnO_ 4 with an oxalate in acidic medium, MnO_ 4 ^ - is reduced to Mn^ 2+ and C_ 2 O_ 4 ^ 2- is oxidised to CO_ 2 . Hence, 50 mL of 0.02 M KMnO_ 4 is equivalent

BITSAT 2012 Solution View → 22

Related BITSAT Chemistry chapters

General Organic Chemistry (48)Chemical Bonding and Molecular Structure (43)Coordination Compounds (35)Thermodynamics (C) (34)Chemical Kinetics (33)Electrochemistry (29)p Block Elements (Group 15, 16, 17 & 18) (27)Structure of Atom (27)Biomolecules (26)s Block Elements (26)Aldehydes and Ketones (22)Classification of Elements and Periodicity in Properties (22)

Some Basic Concepts of Chemistry in other exams

JEE Some Basic Concepts of Chemistry (432)NEET Some Basic Concepts of Chemistry (370)