A wire mesh consisting of very small squares is viewed at a distance of 8 ~cm through a magnifying converging lens of focal length 10 ~cm , kept close to the eye. The magnification produced by the lens is

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Correct answer: A. 5

u=-8 ~cm, f=10 ~cm As, (1)/(v)-(1)/(u)=(1)/(f) , (1)/(v)=(1)/(f)+(1)/(u)=(1)/(10)+(1)/(-8)=(1)/(10)-(1)/(8)=(4-5)/(40)=(-1)/(40) or, v=-40 ~cm . Magnification produced by the lens, m=(v)/(u)=(-40)/(-8)=5 . This is a virtual image, erect and on the same side as the object.

A wire mesh consisting of very small squares is viewed at a...

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