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BITSAT 2021
Exam
BITSAT
Year
2021
Subject
Chemistry
Chapter
Structure of Atom

BITSAT 2021 · Chemistry · Structure of Atom

The frequency of radiation emitted when the electron falls from n=4...

The frequency of radiation emitted when the electron falls from n=4\mathrm{n}=4 to n=1\mathrm{n}=1 in a hydrogen atom will be (Given : ionization energy of H=2.18×10−18J\mathrm{H}=2.18 \times 10^{-18} \mathrm{ J} atom −1{ }^{-1} and h=6.625×10−34Js\mathrm{h}=6.625 \times 10^{-34} \mathrm{Js} )

Options

  1. A1.54×1015s−11.54 \times 10^{15} \mathrm{ s}^{-1}
  2. B1.03×1015s−11.03 \times 10^{15} \mathrm{ s}^{-1}
  3. C3.08×1015s−13.08 \times 10^{15} \mathrm{ s}^{-1}
  4. D2.00×1015s−12.00 \times 10^{15} \mathrm{ s}^{-1}

Correct answer

C. 3.08×1015s−13.08 \times 10^{15} \mathrm{ s}^{-1}

Step-by-step solution

v=1h×IE×[1n12−1n22]=2.18×10−186.625×10−34×[11−116]=3.08×1015s−1\begin{aligned} \mathrm{v} &=\frac{1}{\mathrm{ h}} \times \mathrm{IE} \times\left[\frac{1}{\mathrm{n}_{1}{ }^{2}}-\frac{1}{\mathrm{n}_{2}{ }^{2}}\right] \\ &=\frac{2.18 \times 10^{-18}}{6.625 \times 10^{-34}} \times\left[\frac{1}{1}-\frac{1}{16}\right]=3.08 \times 10^{15} \mathrm{ s}^{-1} \end{aligned}
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