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BITSAT 2015
Exam
BITSAT
Year
2015
Subject
Mathematics
Chapter
Application of Derivatives

BITSAT 2015 · Mathematics · Application of Derivatives

If (0< x< (π)/(2) ), then

If (0< x< π2\frac{\pi}{2}), then

Options

  1. A(\tan x< x< \sin x)
  2. B(x< \sin x< \tan x)
  3. C(\sin x< \tan x< x)
  4. DNone of the above

Correct answer

D. None of the above

Step-by-step solution

Let us assume the functions f(x)\mathrm{f}(\mathrm{x}) and g(x)\mathrm{g}(\mathrm{x}) given by f(x)=tan⁡x−x\mathrm{f}(\mathrm{x})=\tan \mathrm{x}-\mathrm{x} and g(x)=x−sin⁡x,\mathrm{g}(\mathrm{x})=\mathrm{x}-\sin \mathrm{x}, for 0<x<π20\lt \mathrm{x}\lt \frac{\pi}{2} Now, \mathrmf′(x)=sec⁡2x−1\mathrmf^{\prime}(\mathrm{x})=\sec ^{2} \mathrm{x}-1 and \mathrmg′(x)=1−cos⁡x⇒f(x)>0\mathrmg^{\prime}(\mathrm{x})=1-\cos \mathrm{x}\Rightarrow \mathrm{f}(\mathrm{x}) \gt 0 and \mathrmg′(x)>0,∀x∈(0,π2)⇒f(x)>f(0)\mathrmg^{\prime}(\mathrm{x}) \gt 0, \forall \mathrm{x} \in\left(0, \frac{\pi}{2}\right)\Rightarrow \mathrm{f}(\mathrm{x}) \gt \mathrm{f}(0) and g(x)>g(0)∀x∈(0,π2)⇒tan⁡x−x>0\mathrm{g}(\mathrm{x}) \gt \mathrm{g}(0) \forall \mathrm{x} \in\left(0, \frac{\pi}{2}\right)\Rightarrow \quad \tan \mathrm{x}-\mathrm{x} \gt 0 and x−sin⁡x>0,∀x∈(0,π2)⇒tan⁡x>x\mathrm{x}-\sin \mathrm{x} \gt 0,\forall \mathrm{x} \in\left(0, \frac{\pi}{2}\right)\Rightarrow \quad \tan \mathrm{x} \gt \mathrm{x} and \mathrm{x} \gt \sin \mathrm{x}, \forall \mathrm{x} \in\left(0, \frac{\pi}{2}\right)\Rightarrow \quad \sin \mathrm{x}\lt \mathrm{x}\lt \tan \mathrm{x}, \forall \mathrm{x} \in \left(0,\frac{\pi}{2}\right)
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