BITSAT 2011
- Exam
- BITSAT
- Year
- 2011
- Subject
- Mathematics
- Chapter
- Application of Derivatives
BITSAT 2011 · Mathematics · Application of Derivatives
The function (f(x)= x-k x-c), where k and c are constants,...
The function (f(x)=\sin x-k x-c), where and are constants, decreases always when
Options
- A
- B(k \geq 1)
- C
- D(k \leq 1)
Correct answer
B. (k \geq 1)
Step-by-step solution
Let (f(x)=\sin x-k x-c) where and are constants. (f^{\prime}(x)=\cos x-k)
(\therefore f) decreases if (\cos x \leq k)
Thus, (f(x)=\sin x-k x-c) decrease always when (k \geq 1).