If y= ⁻¹ ( x -x 1+x^ 3 2 ) , then y^ (1) is equal to

Step-by-step solution

Given, aligned y & = ⁻¹ ( x -x 1+x^ 3 2 ) y & = ⁻¹ ( x -x 1+ x x ) y & = ⁻¹( x )- ⁻¹ x & [ ⁻¹ ( x-y 1+x y )= ⁻¹ x- ⁻¹ y ] aligned Differentiating w.r.t xy^ (x)= d y d x = 1 1+x 1 2 x - 1 1+x^2 Now, y^ (1)= 1 2 1 2 - 1 2 =- 1 4