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BITSAT2010MathematicsFunctionsActual

A black die and a white die are rolled. Find the probability that the number shown by the black die will be more than twice that shown by the white die.

Options

  1. A(1 / 8 )
  2. B(1 / 6 )
  3. C(1 / 3 )
  4. D(1 / 4 )

Correct answer

B. (1 / 6 )

Step-by-step solution

The number of favourable cases are shown below: ( array cl Number on white die & Number on black die 1 & 3 1 & 4 1 & 5 1 & 6 2 & 5 2 & 6 array ) There are 6 favourable cases in which the number on black die is more than twice the number on the white die. ( aligned & m =6 & n = Total number of cases =6 6 aligned ) ( ( ) with each die there are six possibilities) ( ) Probability ( p = m n = 6 6 6 = 1 6 )

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