BITSAT2019MathematicsLimitsActual
The value of lim x → 3 π 4 4 sin 2 x cos x - cos x + sin x sin x + cos x is
Options
- A- 1
- B0
- C1
- DNone of these
Correct answer
A. - 1
Step-by-step solution
L = lim x → 3 π 4 4 sin 2 x cos x - cos x + sin x sin x + cos x L = lim x → 3 π 4 2 sin x sin 2 x + cos 2 x + 2 sin x cos x - 1 - cos x + sin x sin x + cos x L = lim x → 3 π 4 2 sin x ( sin x + cos x ) 2 - 1 - cos x + sin x sin x + cos x L = lim x → 3 π 4 2 sin x ( sin x + cos x ) 2 - 2 sin x - cos x + sin x sin x + cos x L = lim x → 3 π 4 sin x + cos x 2 sin x sin x + cos x - 1 sin x + cos x L = lim x → 3 π 4 2 sin x sin x + cos x - 1 = - 1