Let f(x)= x, g(x)= x, h(x)=x^2 then _ x 1 f(g(h(x)))-f(g(h(1))) x-1 =

Step-by-step solution

Given f(x)= x, g(x)= x, h(x)=x^2 _ x 1 f(g(h(x)))-f(g(h(1))) x-1 When limit it applied, it gives 0 0 form, so we apply L'Hospital rule. _ x 1 ( x^2 ) (- x^2 )(2 x)-0 1-0 Apply the limit, -2(1) (1) ( 1)=-2 (1) ( 1)