Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
BITSAT2010MathematicsLimitsActual

The minimum value of ( x^4+y^4+z^2 x y z ) for positive real number (x, y, z ) is

Options

  1. A( 2 )
  2. B(2 2 )
  3. C(4 2 )
  4. D(8 2 )

Correct answer

B. (2 2 )

Step-by-step solution

By A.M. ( ) G.M. (x^4+y^4 2 x^2 y^2 ) and (2 x^2 y^2+z^2 8 x y z ). ( x^4+y^4+z^2 x y z 8 )

Practice Limits on Quantrex Academy →

More from Limits

Given a real valued function ' f ' such that f(x)= array cc ^2 x x^2-[x]^2 & for x 0 1 & for x=0 x x & for x 0 array . then 2024Let f(x)= x, g(x)= x, h(x)=x^2 then _ x 1 f(g(h(x)))-f(g(h(1))) x-1 = 2024If f(x)= array l x^2-1,0 < x < 2 2 x+3,2 x < 3 array . , then the quadratic equation whose roots are _ x 2⁻ f(x) and _ x 2⁺ f(x) is 2023_ x 0 | x| x is equal to 2023The value of _ x 0 1- (1- x) x^4 is 2022The value of _ x 0 (1+x)^ 1 x -e+ 1 2 e x x^2 is 2022Value of _ x 0 a^ x -1 x is 2021_ x 0 2 ² 3 x x² is equal to 2021 Full Limits list All BITSAT PYQs