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BITSAT 2023Paper 1
Exam
BITSAT
Year
2023
Paper
Paper 1
Subject
Mathematics
Chapter
Linear Programming

BITSAT 2023 · Paper 1 · Mathematics · Linear Programming

The maximum value of z=5 x+2 y subject to constraints x+y ≤ 7, x+2...

The maximum value of z=5x+2yz=5 x+2 y subject to constraints x+y≤7,x+2y≤10,x,y≥0x+y \leq 7, x+2 y \leq 10, x, y \geq 0The maximum value of z=5 x+2 y subject to constraints x+y ≤ 7, x+2 y ≤ 10, x, y ≥ 0

Options

  1. A10
  2. B26
  3. C35
  4. D70

Correct answer

C. 35

Step-by-step solution

Change the inequalities into equations and draw the graph of lines, thus we get the required feasible region as shown below.
The maximum value of z=5 x+2 y subject to constraints x+y ≤ 7, x+2 y ≤ 10, x, y ≥ 0

The region bounded by the vertices A(0,5),B(4,3),C(7,0)A(0,5), B(4,3), C(7,0)
The objective function is maximum at C(7,0)\mathrm{C}(7,0) and Max⁡z=5×7+2×0=35\operatorname{Max} z=5 \times 7+2 \times 0=35.
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