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BITSAT2018MathematicsLinear ProgrammingActual

The maximum value of Z = 4 x + 2 y subject to constraints 2 x + 3 y ≤ 18 , x + y ≥ 10 and x , y ≥ 0 is

Options

  1. A20
  2. B36
  3. C40
  4. DNone of these

Correct answer

D. None of these

Step-by-step solution

We have, Z = 4 x + 2 y And, 2 x + 3 y ≤ 18 ,   x + y ≥ 10 Let L 1 : 2 x + 3 y = 18 L 2 :   x + y = 10 L 3 : x = 0 L 4 : y = 0 Then the feasible region is From the figure, it is clear that there is no common area. So, we cannot find maximum value of Z . Hence, option d is correct.

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