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BITSAT2020MathematicsLinear ProgrammingActual

The maximum value of z=6 x+8 y subject to constraints 2 x+y 30, x+2 y 24 and x 0, y 0 is

Options

  1. A90
  2. B120
  3. C96
  4. D240

Correct answer

B. 120

Step-by-step solution

Here, 2 x+y 30, x+2 y 24, x, y 0 The shaded region represents the feasible region, hence z =6 x +8 y . Obviously it is maximum at (12,6) Hence z=12 6+8 6=120

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