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BITSAT 2018

Exam: BITSAT
Year: 2018
Subject: Mathematics
Chapter: Mathematical Reasoning

BITSAT 2018 · Mathematics · Mathematical Reasoning

If p: 4 is an even prime number, q: 6 is a divisor of 12 and r: the...

If

p: 4

is an even prime number,

q: 6

is a divisor of

12

and

r:

the

HCF

of

4

and

6

is

2

, then which of the following is correct?

Options

A $\left(p ∧ q\right)$
B $\left(p ∨ q\right) ∧ ~ r$
C $~ \left(q ∧ r\right) ∨ p$
D $p ∨ \left(q ∧ r\right)$

Correct answer

D. $p ∨ \left(q ∧ r\right)$

Step-by-step solution

Since, $p: 4$ is an even prime number,

$q: 6$ is a divisor of $12$ and

$r:$ the $HCF$ of $4$ and $6$ is $2$ .

So, $p ∨ \left(q ∧ r\right) is correct.</p><p>Hence, option (d) is correct.</p>$

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