Quantrex AcademyPYQs with solutions · JEE · NEET · NDA

Home · BITSAT PYQs · Mathematics · Mathematical Reasoning

BITSAT Mathematical Reasoning PYQs with Solutions

14 previous year questions from Mathematical Reasoning (BITSAT Mathematics) with answers and solutions. Numbered list, year tags, and one-tap solutions — built for serious JEE / NEET practice.

14 questionsMathematics2009–2024Answers + solutions

About Mathematical Reasoning PYQs

Mathematical Reasoning has 14 previous year questions in the Quantrex Academy BITSAT Mathematics bank. The 14 questions in this list come from BITSAT (14), spanning 2009 to 2024. Each question opens on its own page with the options, the correct answer and the worked solution where available.

Questions by year (this list)

2024: 6
2023: 2
2021: 1
2018: 2
2013: 1
2011: 1
2009: 1

Mathematical Reasoning questions with solutions

The Boolean expression ∼(p ∨ q) ∨(∼ p ∧ q) is equivalent to

BITSAT 2024 Solution View → 2

If p: 2 is an even number q: 2 is a prime number, r: 2+2=2^2 Then the symbolic statement p arrow(q ∨ r) means

BITSAT 2024 Solution View → 3

Consider the following statements : A: Rishi is a judge. B : Rishi is honest. C: Rishi is not arrogant. The negation of the statement "if Rishi is a judge and he is not arrogant

BITSAT 2024 Solution View → 4

If p : It raining today, q: I go to school, r : I shall meet any friends and s : I shall go for a movie, then which of the following is the proposition : 'If it does not rain or

BITSAT 2024 Solution View → 5

Let p, q, r be three logical statements. Consider the compound statements S_1:((∼ p) ∨ q) ∨((∼ p) ∨ r) and S_2: p arrow(q ∨ r) Then, which of the following is NOT true?

BITSAT 2024 Solution View → 6

Consider the following two propositions: P_1: ∼(p arrow ∼ q)P_2:(p ∧ ∼ q) ∧((∼ p) ∨ q) If the proposition p arrow((∼ p) ∨ q) is evaluated as FALSE, then :

BITSAT 2024 Solution View → 7

The negation of the Boolean expression ((∼ q)∧ p) ⇒((∼ p) ∨ q) is logically equivalent to

BITSAT 2023 Solution View → 8

Negation of the Boolean expression p ⇔(q ⇒ p) is

BITSAT 2023 Solution View → 9

The statement p: For any real numbers x, y if x=y , then 2 x+a=2 y+a when a ∈ Z .

BITSAT 2021 Solution View → 10

Which of the following statement is a tautology?

BITSAT 2018 Solution View → 11

If p: 4 is an even prime number, q: 6 is a divisor of 12 and r: the HCF of 4 and 6 is 2 , then which of the following is correct?

BITSAT 2018 Solution View → 12

Inthetruth table for the statement (p ∧ q) arrow(q ∨ ∼ p) , the last column has the truth value in the following order is

BITSAT 2013 Solution View → 13

Negation of "Paris in France and London is in England" is

BITSAT 2011 Solution View → 14

If \(f(t)=(1-t)/(1+t)\), then \(f^ (1 / t)\) is equal to

BITSAT 2009 Solution View →

Practice all Mathematical Reasoning questions in the app →

Related BITSAT Mathematics chapters

Application of Derivatives (67)Sequences and Series (51)Probability (44)Three Dimensional Geometry (40)Functions (39)Binomial Theorem (34)Permutation and Combination (31)Complex Number (30)Circle (27)Differential Equations (27)Straight Lines (27)Vector Algebra (25)

Mathematical Reasoning in other exams

JEE Mathematical Reasoning (204)