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BITSAT 2024Paper 2

Exam: BITSAT
Year: 2024
Paper: Paper 2
Subject: Mathematics
Chapter: Parabola

BITSAT 2024 · Paper 2 · Mathematics · Parabola

If the focus of parabola (y-k)^2=4(x-h) always lies between the...

If the focus of parabola

(y-k)^2=4(x-h)

always lies between the lines

x+y=1

and

x+y=3

then

If the focus of parabola (y-k)^2=4(x-h) always lies between the lines x+y=1 and x+y=3 then

Options

A $0 < h+k < 2$
B $0 < h+k < 1$
C $1 < h+k < 2$
D $1 < h+k < 3$

Correct answer

A. $0 < h+k < 2$

Step-by-step solution

Coordinate of focus will be

(h+1, k)

Now focus should lie to the opposite side of origin with respect to line

x+y-1=0

and same side as origin with respect to line

x+y-3=0

If the focus of parabola (y-k)^2=4(x-h) always lies between the lines x+y=1 and x+y=3 then

Hence

h+k>0

and

h+k < 2

.

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