Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
BITSAT2019MathematicsParabolaActual

Suppose a parabola y = a x 2 + b x + c has two x intercepts, one positive and one negative, and its vertex is ( 2 , - 2 ) , then which of the following is true?

Options

  1. Aa b > 0
  2. Bb c > 0
  3. Ca c > 0
  4. Da + b + c > 0

Correct answer

B. b c > 0

Step-by-step solution

Given, y = a x 2 + b x + c has two x -intercepts one is positive and one is negative and vertex is ( 2 , - 2 ) . The graph of y = a x 2 + b x + c is Clearly from graph c > 0 - b a > 0 ⇒ - b > 0 ⇒   b < 0 f ( 1 ) = a + b + c < 0 a b < 0 , a c < 0 , b c > 0

Practice Parabola on Quantrex Academy →

More from Parabola

If the focus of parabola (y-k)^2=4(x-h) always lies between the lines x+y=1 and x+y=3 then 2024Let L₁ be the length of the common chord of the curves x^2+y^2=9 and y^2=8 x , and L₂ be the length of the latus rectum of y^2=8 x , then: 2024If vertex of a parabola is (2,-1) and the equation of its directrix is 4 x-3 y=21 , then the length of its latus rectum is 2023The equation of a common tangent to the parabolas y=x^2 and y=-(x-2)^2 is 2023If the straight line y=m x+c touches the parabola y^2-4 a x+4 a^3=0 , then c is 2022A normal is drawn at the point P to the parabola y^2=8 x , which is inclined at 60^ with the straight line y=8 . Then the point P lies on the straight line 2022The length of the latus rectum of the parabola which has focus at (-1,1) and the directrix is 4 x +3 y-24=0 is 2020Normals drawn to y 2 = 4 a x at the points where it is intersected by the line y = m x + c intersected at P . Coordinates of foot of the another normal drawn to the parabola from t 2018 Full Parabola list All BITSAT PYQs