Suppose a parabola y = ax^ 2 + bx + c has two x intercepts, one...

Given, $y = ax^{2} + bx + c$ has two $x$-intercepts one is positive and one is negative and vertex is $( 2, - 2 )$. The graph of $y = ax^{2} + bx + c$ is

Clearly from graph

$c > 0$

$- \dfrac{b}{a} > 0 ⇒ - b > 0$

$⇒ b < 0$

$f ( 1 ) = a + b + c < 0$

$ab 0$