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AIIMS 2005
Exam
AIIMS
Year
2005
Subject
Physics
Chapter
Units and Dimensions

AIIMS 2005 · Physics · Units and Dimensions

Dimension of electrical resistance is

Dimension of electrical resistance is

Options

  1. A[ML2 T−3 A−1]\left[\mathrm{ML}^2 \mathrm{~T}^{-3} \mathrm{~A}^{-1}\right]
  2. B[ML2 T−3 A−2]\left[\mathrm{ML}^2 \mathrm{~T}^{-3} \mathrm{~A}^{-2}\right]
  3. C[ML3 T−3 A−2]\left[\mathrm{ML}^3 \mathrm{~T}^{-3} \mathrm{~A}^{-2]}\right.
  4. D[ML−1 L3 T3 A2]\left[\mathrm{ML}^{-1} \mathrm{~L}^3 \mathrm{~T}^3 \mathrm{~A}^2\right].

Correct answer

B. [ML2 T−3 A−2]\left[\mathrm{ML}^2 \mathrm{~T}^{-3} \mathrm{~A}^{-2}\right]

Step-by-step solution

 Resistance = potential difference  current =ML2T−3A−1A=[ML2T−3A−2]\begin{aligned}\text{ Resistance }& =\frac{\text{ potential difference }}{\text{ current }}\\ & =\frac{\mathrm{ML}^2 \mathrm{ T}^{-3} \mathrm{ A}^{-1}}{\mathrm{ A}}=\left[\mathrm{ML}^2 \mathrm{ T}^{-3} \mathrm{ A}^{-2}\right] \end{aligned}
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