Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
BITSAT2024MathematicsProbabilityActual

In a binomial distribution, the mean is 4 and variance is 3 . Then, its mode is

Options

  1. A5
  2. B6
  3. C4
  4. DNone of these

Correct answer

C. 4

Step-by-step solution

aligned Mean & =n p=4 Variance & =n p q=3 q & = 3 4 aligned and p=1-q=1- 3 4 = 1 4 n=16 Now, Mode of Binomial distribution is given by (n+1) P Case IIf (n+1) P= Integer (I) , then Mode = I, I-1 Case II If (n+1) P Integer (I+f) , then Mode = I aligned (n+1) P & =(16+1) 1 4 & = 17 4 =4.25 & =4+0.25 Mode & =4 aligned

Practice Probability on Quantrex Academy →

More from Probability

The probability of getting 10 in a single throw of three fair dice is 2024The probability that certain electronic component fails when first used is 0.10 . If it does not fail immediately, the probability that it lasts for one year is 0.99 . The probabil 2024Given below is the distribution of a random variable X If = P (X 3) and = P (X 2) , then : = 2024A book contains 1000 pages. A page is chosen at random. The probability that the sum of the digits of the marked number on the page is equal to 9 , is 2024For two events A and B , if P ( A )= P ( A B )= 1 4 and P ( B A )= 1 2 , then which of the following is not true? 2024If A and B are mutually exclusive events and if P ( B )= 1 3 , P ( A B )= 13 21 , then P ( A ) is equal to 2023A coin is tossed twice. Then, the probability that atleast one tail occurs is 2023If E and F are events such that 0 < P ( F ) < 1 , then 2023 Full Probability list All BITSAT PYQs