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BITSAT2021MathematicsProbabilityActual

The mean and variance of a random variable X having binomial distribution are 4 and 2 respectively, then P ( X =1) is

Options

  1. A1 4
  2. B1 32
  3. C1 16
  4. D1 8

Correct answer

B. 1 32

Step-by-step solution

aligned n p &=4 n p q &=2 q &= 1 2 , p= 1 2 , n=8 P ( X &=1)= ⁸ C ₁ ( 1 2 ) ( 1 2 )⁷=8 1 2⁸ = 1 2⁵ = 1 32 aligned

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