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BITSAT2023MathematicsProbabilityActual

The probability of getting sum more than 7 when a pair of dice are thrown is:

Options

  1. A7 36
  2. B5 12
  3. C7 12
  4. DNone of these

Correct answer

B. 5 12

Step-by-step solution

Here n(S)=6^2=36 Let E be the event "getting sum more than 7" i.e. sum of pair of dice =8,9,10,11,12 i.e. E= array lllll (2,6) & (3,5) & (4,4) & (5,3) & (6,2) (3,6) & (4,5) & (5,4) & (6,3) (4,6) & (5,5) & (6,4) & (5,6) & (6,5) & (6,6) & array n(E)=15 . Req. prob = n(E) n(S) = 15 36 = 5 12

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