Which of the following pairs does not have same dimensions ?

Impulse $=F \times t$ $$=\frac{m\left(v_2-v_1\right)}{t} \times t=m\left(v_2-v_1\right)$$ = change in momentum $\therefore \quad$ [Impulse $]=[$ Momentum $]$ Angular momentum, $\mathrm{L}=m v r$ Planck's constant, $[h]=[$ energy $] \times[$ time $]$ $$\Rightarrow[F \times r \times \text{ time })=\frac{m\left(v_2-v_1\right)}{t} \times r \times t$$ $\Rightarrow m\left(v_2-v_1\right) \times r=($ change of momentum $) \times r$ $\therefore \quad[h]=[L]$. Work, $W=\vec{F} \cdot \vec{d}:$ Torque, $\tau=\vec{r} \times \vec{F}$ $$\therefore \quad[W]=[\tau]$$ Moment of inertia, $I=m r^2=\operatorname{mass} \times(\text{ distance })^2$ Moment of force, $\tau=\vec{r} \times \vec{F}=$ distance $\times$ force \begin{aligned} & \quad=\text{ distance } \times \frac{\text{ change of momentum }}{\text{ time }} \\ & \therefore \quad[\mathrm{I}] \neq[\tau] . \end{aligned} Therefore, moment of inertia and moment of force have different dimensions.