The distance of the point ((-1,1) ) from the line (12(x+6)=5(y-2) ) is

Step-by-step solution

The given line is (12(x+6)=5(y-2) ) ( 12 x+72=5 y-10 ) or (12 x-5 y+72+10=0 12 x-5 y+82=0 ) The perpendicular distance from ( (x₁, y₁ ) ) to the line (a x+b y+c=0 ) is ( ( ax ₁+ by ₁+ c ) a ^2+ b ^2 ). The point ( (x₁, y₁ ) ) is ((-1,1) ), therefore, perpendicular distance from ((-1,1) ) to the line (12 x-5 y+82=0 ) is (= |-12-5+82| 12^2+(-5)^2 = 65 144+25 = 65 169 =5 )