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BITSAT 2018
Exam
BITSAT
Year
2018
Subject
Mathematics
Chapter
Three Dimensional Geometry

BITSAT 2018 · Mathematics · Three Dimensional Geometry

A line makes angles α, β, γ with the coordinate axes. If α + β =...

A line makes angles α,β,γ\alpha, \beta, \gamma with the coordinate axes. If α+β=π2\alpha + \beta = \dfrac{π}{2},~then (cosα+cosβ+cosγ)2\left(cos\alpha + cos\beta + cos\gamma\right)2 is equal to

Options

  1. A1+sin⁡2α1 + \sin 2\alpha
  2. B1−sin⁡2α1 - \sin 2\alpha
  3. C1+cos⁡2α1 + \cos 2\alpha
  4. DNone of these

Correct answer

A. 1+sin⁡2α1 + \sin 2\alpha

Step-by-step solution

We have, cos⁡2α+cos⁡2β+cos⁡2γ=1\cos^{2}\alpha + \cos^{2}\beta + \cos^{2}\gamma = 1

⇒cos⁡2α+cos⁡2(π2−α)+cos⁡2γ=1⇒ \cos^{2}\alpha + \cos^{2}\left(\dfrac{\pi}{2} - \alpha\right) + \cos^{2}\gamma = 1 [given α+β=π2\alpha + \beta = \dfrac{\pi}{2}]

⇒cos⁡2α+sin⁡2α+cos⁡2γ=1⇒ \cos^{2}\alpha + \sin^{2}\alpha + \cos^{2}\gamma = 1

⇒1+cos⁡2γ=1⇒ 1 + \cos^{2}\gamma = 1

⇒cos⁡2γ=0⇒ \cos^{2}\gamma = 0

⇒cosγ=0⇒ cos\gamma = 0

∴(cosα+cosβ+cosγ)2=(cosα+sinα)2∴ \left(cos\alpha + cos\beta + cos\gamma\right)^{2} = \left(cos\alpha + sin\alpha\right)^{2}

=1+2sinα⋅cosα=1+sin⁡2α= 1 + 2sin\alpha \cdot cos\alpha = 1 + \sin 2\alpha

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