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BITSAT 2018
Exam
BITSAT
Year
2018
Subject
Mathematics
Chapter
Three Dimensional Geometry

BITSAT 2018 · Mathematics · Three Dimensional Geometry

If the planes → r · (2 ^ i - λ ^ j + 3 ^ k ) = 0 and → r · (λ ^ i +...

If the planes \overset{→}{r} \cdot \left(2\overset{^}{i} - \lambda\overset{^}{j} + 3\overset{^}{k}\right) = 0 and \overset{→}{r} \cdot \left(\lambda\overset{^}{i} + 5\overset{^}{j} - \overset{^}{k}\right) = 5 are perpendicular to each other, then the value of λ2+λ{λ}^{2} + \lambda is

Options

  1. A00
  2. B22
  3. C11
  4. D33

Correct answer

A. 00

Step-by-step solution

We have,

\overset{→}{r} \cdot \left(\lambda\overset{^}{i} + 5\overset{^}{j} - \overset{^}{k}\right) = 5

\overset{→}{r} \cdot \left(2\overset{^}{i} - \lambda\overset{^}{j} + 3\overset{^}{k}\right) = 0

We know that two planes~r→⋅n→1=d1\overset{→}{r} \cdot \overset{→}{n}1 = {d}_{1}~and& r→⋅n→2=d2\overset{→}{r} \cdot \overset{→}{n}2 = {d}_{2}~are perpendicular if

n→1⋅n→2=0\overset{→}{n}1 \cdot \overset{→}{n}2 = 0

Therefore,

\left(\lambda\overset{^}{i} + 5\overset{^}{j} - \overset{^}{k}\right) \cdot \left(2\overset{^}{i} - \lambda\overset{^}{j} + 3\overset{^}{k}\right) = 0</p><p></p><p>⇒ 2\lambda - 5\lambda - 3 = 0</p><p></p><p>⇒ - 3\lambda - 3 = 0</p><p></p><p>⇒ \lambda = - 1</p><p>Therefore, </p><p>Therefore,~{λ}^{2} + \lambda = 0

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