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BITSAT 2009
Exam
BITSAT
Year
2009
Subject
Mathematics
Chapter
Three Dimensional Geometry

BITSAT 2009 · Mathematics · Three Dimensional Geometry

If the line ( (x-4)/(1)=(y-2)/(1)=(z-k)/(2) ) lies in the plane 2...

If the line (x−41=y−21=z−k2\frac{x-4}{1}=\frac{y-2}{1}=\frac{z-k}{2}) lies in the plane 2x−4y+z=72 x-4 y+z=7, then the value of kk is

Options

  1. A4
  2. B-7
  3. C7
  4. DNo real value

Correct answer

C. 7

Step-by-step solution

The point (4,2,k)(4,2, k) on the line also lies on the plane 2x−4y+z=72 x-4 y+z=7 So, (8-8+k=\mathrm{k}=7 \Rightarrow k=\mathrm{k}=7)
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