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BITSAT2024PhysicsAlternating CurrentActual

An alternating voltage V(t)=220 100 t volt is applied to a purely resistive load of 50 . The time taken for the current to rise from half of the peak value to the peak value is:

Options

  1. A5 ms
  2. B3.3 ms
  3. C7.2 ms
  4. D2.2 ms

Correct answer

B. 3.3 ms

Step-by-step solution

Rising half to peak t=T / 6 t = 2 6 = 3 = 300 = 1 300 =3.3 ~ms Here =100 rad / s

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