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BITSAT2022PhysicsAlternating CurrentActual

In the circuit shown in the figure, the AC source gives a voltage V=20 (2000 t) neglecting source resistance, the voltmeter and ammeter reading will be

Options

  1. A0 ~V , 0.47 ~A
  2. B282 ~V , 1.41 ~A
  3. C1.41 ~V , 0.47 ~A
  4. D15 ~V , 837 ~A

Correct answer

B. 282 ~V , 1.41 ~A

Step-by-step solution

Given, R₁=8 aligned R₂ & =2 L & =5 mH C & =50 F aligned and V₀=20 (2000 t) Impedance, Z= R^2+ (X_L-X_C )^2 As, here, X_L= L=2000 5 10⁻³=10 Similarly, X_L= 1 C = 1 2000 50 10⁻⁶ =10 X_L=X_C , Hence, i_ = V₀ Z = 20 (8+2) =2 ~A Hence, i_ rms = i_ 2 = 2 2 =1.41 ~A and aligned V & =R₂ i_ rms =1.41 2 & =282 ~V aligned

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