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BITSAT2017PhysicsAtomic PhysicsActual

The total energy of an electron in the first excited state of hydrogen is about - 3 . 4 eV . Its kinetic energy in this state is

Options

  1. A- 3 . 4   eV
  2. B- 6 . 8   eV
  3. C6 . 8   eV
  4. D3 . 4   eV

Correct answer

D. 3 . 4   eV

Step-by-step solution

We have, Kinetic energy of electron, K = Z e 2 8 π ε 0 · r also, Potential energy of electron, U = - 1 4 π ε 0 · Z e 2 r ∴ Total energy E = K + U = Z e 2 8 π ε 0 · r - Z e 2 4 π ε 0 · r E = - Z e 2 8 π ε 0 r or K = - E = - - 3 . 4 = 3 . 4   eV

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