BITSAT2009PhysicsAtomic PhysicsActual
Taking Rydberg's constant R _ H =1.097 10⁷ ~m , first and second wavelength of Balmer series in hydrogen spectrum is
Options
- A2000 ~A , 3000 ~A
- B1575 ~A , 2960 ~A
- C6529 ~A , 4280 ~A
- D6552 ~A , 4863 ~A
Correct answer
D. 6552 ~A , 4863 ~A
Step-by-step solution
1 = R [ 1 n ₁² - 1 n ₂² ] . For first wavelength, n ₁ =2, n ₂=3 ₁=6563 . For second wavelength, n ₁=2, n ₂=4 ₂=4861