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BITSAT2020PhysicsCapacitanceActual

In the circuit given below, the charge in C , on the capacitor having 5 F is

Options

  1. A4.5
  2. B9
  3. C7
  4. D15

Correct answer

B. 9

Step-by-step solution

Potential difference across the branch de is 6 ~V . Net capacitance of de branch is 2.1 F So, q=C V q =2.1 6 C q =12.6 C Potential across 3 F capacitance is V = 12.6 3 =4.2 volt Potential across 2 and 5 combination in parallel is 6-4.2=1.8 ~V So, q^ =(1.8)(5)=9 C

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