BITSAT2019PhysicsCapacitanceActual
A charged capacitor of capacitance C is discharging through a resistor of resistance R . At what time the charge on the capacitor is equal to one half of its initial value?
Options
- AR C 2
- BR C log e 2
- CR C log e   2
- D1 R C log e 2
Correct answer
C. R C log e   2
Step-by-step solution
The charge on the capacitor at time t in a discharging circuit is given by q = q 0 e - t / τ where, τ = R C = time constant ∴ q = q 0 e - t / R C when,    q = q 0 2 then q 0 2 = q 0 e - t / R C 1 2 = e - t / R C Taking natural log on both side log e 1 2 = log 0 e - t / R C - log e 2 = - t R C log e e ⇒ t = R C log e 2