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BITSAT 2014
Exam
BITSAT
Year
2014
Subject
Physics
Chapter
Center of Mass, Momentum and Collision

BITSAT 2014 · Physics · Center of Mass, Momentum and Collision

A rifle man, who together with his rifle has a mass of 100 kg ,...

A rifle man, who together with his rifle has a mass of 100kg100 \mathrm{ kg}, stands on a smooth surface and fires 10 shots horizontally. Each bullet has a mass 10g10 \mathrm{ g} and a muzzle velocity of 800ms−1800 \mathrm{ ms}^{-1}. The velocity which the rifle man attains after firing 10 shots is

Options

  1. A8ms−18 \mathrm{ ms}^{-1}
  2. B0.8ms−10.8 \mathrm{ ms}^{-1}
  3. C0.08ms−10.08 \mathrm{ ms}^{-1}
  4. D−0.8ms−1-0.8 \mathrm{ ms}^{-1}

Correct answer

B. 0.8ms−10.8 \mathrm{ ms}^{-1}

Step-by-step solution

According to law of conservation of momentum, 100v=−101000×10×800 i.e., v=0.8ms−1\begin{array}{l}100 \mathrm{v}=-\frac{10}{1000} \times10 \times800 \\ \text{ i.e., } \mathrm{v}=0.8 \mathrm{ ms}^{-1} \end{array}
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