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BITSAT 2017
Exam
BITSAT
Year
2017
Subject
Physics
Chapter
Dual Nature of Matter

BITSAT 2017 · Physics · Dual Nature of Matter

The de-Broglie wavelength of a proton (charge = 1. 6 × 10 ^ - 19 C,...

The de-Broglie wavelength of a proton (charge =1.6×10−19C,m=1.6×10−27kg= 1. 6 \times {10}^{- 19}C, m = 1. 6 \times {10}^{- 27}kg) accelerated through a potential difference of 1kV1kV is&

Options

  1. A600Å600 Å
  2. B0.9×10−12m0. 9 \times {10}^{- 12}m
  3. C7Å7 Å
  4. D0.9nm0. 9nm

Correct answer

B. 0.9×10−12m0. 9 \times {10}^{- 12}m

Step-by-step solution

de-Broglie wavelength,

λ=hp=h2mE=h2mqV\lambda = \dfrac{h}{p} = \dfrac{h}{2mE} = \dfrac{h}{2mqV}

⇒λ=6.6×10−342×1.6×10−27×1.6×10−19×1000⇒ \lambda = \dfrac{6. 6 \times {10}^{- 34}}{2 \times 1. 6 \times {10}^{- 27} \times 1. 6 \times {10}^{- 19} \times 1000}

⇒λ=6.6×10−347.16×10−22=0.9×10−12m⇒ \lambda = \dfrac{6. 6 \times {10}^{- 34}}{7. 16 \times {10}^{- 22}} = 0. 9 \times {10}^{- 12}m

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