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BITSAT 2024Paper 1
Exam
BITSAT
Year
2024
Paper
Paper 1
Subject
Physics
Chapter
Electromagnetic Induction

BITSAT 2024 · Paper 1 · Physics · Electromagnetic Induction

A rectangular loop of length 2.5 m and width 2 m is placed at 60^ ^...

A rectangular loop of length 2.5 m and width 2 m is placed at 60∘60^{{}^{\circ}} to a magnetic field of 4 T. The loop is removed from the field in 10 sec. The average emf induced in the loop during this time is

Options

  1. A−2V-2 \mathrm{ V}
  2. B+2V+2 \mathrm{ V}
  3. C+1V+1 \mathrm{ V}
  4. D−1V-1 \mathrm{ V}

Correct answer

C. +1V+1 \mathrm{ V}

Step-by-step solution

Averageemf, e= Changein flux  Time =−ΔϕΔt=−0−(4×(2.5×2)cos⁡60∘)10=+1\mathrm{e}=\frac{\text{ Changein flux }}{\text{ Time }}=-\frac{\Delta \phi}{\Delta \mathrm{t}}=-\frac{0-\left(4 \times(2.5 \times 2) \cos 60^{{}^{\circ}}\right)}{10}=+1V\mathrm{ V}
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