A conducting loop of radius 10 cm is placed perpendicular to a uniform magnetic field of 0.5 T . The magnetic field is decreased to zero in 0.5 s at a steady rate. The induced emf in the circular loop at 0.25 s is:

Step-by-step solution

As . |_ t=0.5 sec =- d dt =- A dB dt [ =0^ =1 ] =- ( 10 )^2 10⁻⁴ 0-0.5 0.5 =10⁻² ~V =10 mV As d B d t = constant Induced emf will not change with time. So, . e |_ 0,5 sec = . e |_ 0.25 sec =10 mV