BITSAT 2024Paper 2
- Exam
- BITSAT
- Year
- 2024
- Paper
- Paper 2
- Subject
- Physics
- Chapter
- Electrostatics
BITSAT 2024 · Paper 2 · Physics · Electrostatics
If two charges q_1 and q_2 are separated with distance ' d ' and...
If two charges and are separated with distance ' ' and placed in a medium of dielectric constant . What will be the equivalent distance between charges in air for the same electrostatic force ?
Options
- A
- B
- C
- D
Correct answer
A.
Step-by-step solution
As. (air)=(medium)
\Rightarrow \frac{1}{4 \pi \epsilon_0} \frac{\mathrm{q}_1 \mathrm{q}_2}{\mathrm{ d}_{\text{air }^2}=\frac{1}{\mathrm{ K}} \frac{1}{4 \pi \epsilon_0} \frac{\mathrm{q}_1 \mathrm{q}_2}{\mathrm{ d}^2} \Rightarrow \mathrm{ d}_{\text{air }}=\mathrm{d} \sqrt{\mathrm{K}}