In a cuboid of dimension 2 ~L 2 ~L L , a charge q is placed at the centre of the surface ' S ' having area of 4 ~L ^2 . The flux through the opposite surface to ' S ' is given by

Step-by-step solution

After placing similar cubic at the bottom, we get cube of side 2 ~L having change q at its centre. From the Gauss's law electric flux through whole Flux passing through shaded face = q / ₀ 6 = q 6 ₀