In a cuboid of dimension 2 L × 2 L × L , a charge q is placed at the centre of the surface ' S ' having area of 4 L^2 . The flux through the opposite surface to ' S ' is given by

Question

Quantrex Academy · Accepted Answer

Correct answer: D. (q)/(6 _0)

After placing similar cubic at the bottom, we get cube of side

2 \mathrm{ L}

having change

\mathrm{q}

at its centre.

From the Gauss's law electric flux through whole
In a cuboid of dimension 2 L × 2 L × L , a charge q is placed at the centre of the surface ' S ' having area of 4 L^2 .

In a cuboid of dimension 2 L × 2 L × L , a charge q is placed at the centre of the surface ' S ' having area of 4 L^2 .

Flux passing through shaded face

\phi=\frac{\mathrm{q} / \varepsilon_0}{6}=\frac{\mathrm{q}}{6 \varepsilon_0}

In a cuboid of dimension 2 L × 2 L × L , a charge q is placed at...

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