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BITSAT2024PhysicsElectrostaticsActual

Electric potential at a point 'P' due to a point charge of 5 10⁻⁹ C is 50 V . The distance of ' P ' from the point charge is: (Assume, 1 4 ₀ =9 10⁺⁹ Nm ^2 C ⁻² )

Options

  1. A3 cm
  2. B9 cm
  3. C90 cm
  4. D0.9 cm

Correct answer

C. 90 cm

Step-by-step solution

Electric potential at a point P due to a point charge, ( K =9 10^9 )V_P= K Q r 50= 9 10^9 5 10⁻⁹ r r = 45 50 = 9 10 =0.9 ~m =90 ~cm

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