BITSAT 2024Paper 2
- Exam
- BITSAT
- Year
- 2024
- Paper
- Paper 2
- Subject
- Physics
- Chapter
- Electrostatics
BITSAT 2024 · Paper 2 · Physics · Electrostatics
Electric potential at a point 'P' due to a point charge of 5 × 10^...
Electric potential at a point 'P' due to a point charge of is 50 V. The distance of ' P ' from the point charge is:
(Assume, )
Options
- A3 cm
- B9 cm
- C90 cm
- D0.9 cm
Correct answer
C. 90 cm
Step-by-step solution
Electric potential at a point P due to a point charge, \left(\because \mathrm{K}=9 \times 10^9\right)V_P=\frac{K Q}{r}\Rightarrow \quad 50=\frac{9 \times 10^9 \times 5 \times 10^{-9}}{\mathrm{r}}\Rightarrow \quad \mathrm{r}=\frac{45}{50}=\frac{9}{10}=0.9 \mathrm{ m}=90 \mathrm{ cm}