A solenoid of 1200 turns is wound uniformly in a single layer on a glass tube 2 ~m long and 0.2 ~m in diameter. The magnetic intensity at the center of the solenoid when a current of 2 A flows through it is:

Step-by-step solution

Given that number of turns, n=1200 Current, I =2 ~A Magnetic field at centre inside the solenoid is given by, B = ₀ nI So magnetic intensity at centre of the solenoid, aligned & H = B ₀ = nI = ( 1200 2 )(2) ( B = ₀ H ) & H =1.2 10^3 Am ⁻¹ aligned