A charge particle is moving in a uniform magnetic field (2 i +3 j ) T . If it has an acceleration of ( i -4 j ) m / s ^2 , then the value of will be :

Step-by-step solution

Given that uniform magnetic field, B =(2 i +3 j ) T Acceleration a =( i -4 j ) m / s ^2 We know that F=q( v B ) m a =q( v B ) Here, a B , so, a B =0 ( i -4 j )(2 i +3 j )=0 2 -12=0 =6