A cube of ice floats partly in water and partly in kerosene oil. The radio of volume of ice immersed in water to that in kerosene oil (specific gravity of Kerosene oil =0.8 , specific gravity of ice =0.9)

Step-by-step solution

Let V₁ be, the volume immersed in water. V₂ be the volume immersed in oil. In equilibrium condition, v₁ _w g+v₂ ₀ g= (v₁+v₂ ) _e gv₁+ v₂ ₀ _w = (v₁+v₂ ) _c _w v₁+0.8 v₂=0.9 v₁+0.9 v₂ 0.1 v₁=0.1 v₂ v₁: v₂=1: 1