A vessel with water is placed on a weighing pan and it reads 600 g . Now a ball of mass 40 g and density 0.80 g cm^ -3 is sunk into the water with a pin of negligible volume, as shown in figure keeping it sunk. The

Correct answer: C. 650 g Volume of ball =(40)/(0.8)=50 cm^ 3 Downthrust on water =50 g . Therefore reading is 650 g .

BITSAT 2020

Exam: BITSAT
Year: 2020
Subject: Physics
Chapter: Mechanical Properties of Fluids

BITSAT 2020 · Physics · Mechanical Properties of Fluids

A vessel with water is placed on a weighing pan and it reads 600 g...

A vessel with water is placed on a weighing pan and it reads

600 \mathrm{ g}

. Now a ball of mass

40 \mathrm{ g}

and density

0.80 \mathrm{ g} \mathrm{ cm}^{-3}

is sunk into the water with a pin of negligible volume, as shown in figure keeping it sunk. The weighing pan will show a reading A vessel with water is placed on a weighing pan and it reads 600 g . Now a ball of mass 40 g and density 0.80 g cm^ -3

A vessel with water is placed on a weighing pan and it reads 600 g . Now a ball of mass 40 g and density 0.80 g cm^ -3

Options

A $600 \mathrm{ g}$
B $550 \mathrm{ g}$
C $650 \mathrm{ g}$
D $632 \mathrm{ g}$

Correct answer

C. $650 \mathrm{ g}$

Step-by-step solution

Volume of ball

=\frac{40}{0.8}=50 \mathrm{ cm}^{3}

Downthrust on water

=50 \mathrm{ g}

. Therefore reading is

650 \mathrm{ g}

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