Young's moduli of the material of wires A and B are in the ratio of $1: 4$ , while its area of cross sections are in the ratio of $1: 3$ . If the same amount of load is applied to both the wires, the amount of elongation produced in the wires $\mathrm{A}$ and $B$ will be in the ratio of
[Assume length of wires A and B are same]

Question

Young's moduli of the material of wires A and B are in the ratio of

1: 4

, while its area of cross sections are in the ratio of

1: 3

. If the same amount of load is applied to both the wires, the amount of elongation produced in the wires

\mathrm{A}

and

B

will be in the ratio of
[Assume length of wires A and B are same]

Quantrex Academy · Accepted Answer

Correct answer: B. 12 : 1

Elongation produced in the wire is given b Δ L= FL AY Here, L= length of wire A= area of cross-section of wire Y= Young's moduli of material of wire. F and L is same and aligned & Y_ A Y_ B =(1)/(4) (given) & A_ A A_ B =(1)/(3) (given) & Δ L_ A Δ L_ B = A_ B A_ A Y_ B Y_ A =(3)/(1) × (4)/(1)=12 aligned

Young's moduli of the material of wires A and B are in the ratio of...

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