Young's moduli of the material of wires A and B are in the ratio of 1: 4 , while its area of cross sections are in the ratio of 1: 3 . If the same amount of load is applied to both the wires, the amount of elongation produced in the wires A and B will be in the ratio of [Assume length of wires A and B are same]

Step-by-step solution

Elongation produced in the wire is given b L = FL AY Here, L= length of wire A= area of cross-section of wire Y = Young's moduli of material of wire. F and L is same and aligned & Y _ A Y _ B = 1 4 (given) & A _ A A _ B = 1 3 (given) & L _ A L _ B = A _ B A _ A Y _ B Y _ A = 3 1 4 1 =12 aligned