There are two wire of same material and same length while the diameter of second wire is two times the diameter of first wire, then the ratio of extension produced in the wires by applying same load will be

Step-by-step solution

Both wires are same materials so both will have same Young's modulus, and let it be Y. Y= stress strain = F A. ( L / L) , F= applied force A = area of cross-section of wire Now, Y ₁= Y ₂ FL ( A ₁ ) ( L ₁ ) = FL ( A ₂ ) ( L ₂ ) Since load and length are same for both array l r ₁² L ₁= r ₂² L ₂, ( L ₁ L ₂ )= ( r ₂ r ₁ )²=4 L ₁: L ₂=4: 1 array