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BITSAT 2018
Exam
BITSAT
Year
2018
Subject
Physics
Chapter
Mechanical Properties of Solids

BITSAT 2018 · Physics · Mechanical Properties of Solids

Breaking stress of a steel wire is p and the density of steel is ρ...

Breaking stress of a steel wire is pp and the density of steel is ρρ. The greatest length of steel wire that can hang vertically without breaking is

Options

  1. Apρg\dfrac{p}{ρg}
  2. Bp2ρg\dfrac{p}{2ρg}
  3. C2pρg\dfrac{2p}{ρg}
  4. DNone of these

Correct answer

A. pρg\dfrac{p}{ρg}

Step-by-step solution

Maximum stress =MaximumweightCross−sectionalarea= \dfrac{Maximumweight}{Cross - sectionalarea}

Now, maximum weight of steel wire

= Volume ×\times Density ×g=Alρg\times g= Alρg

where, ll is the maximum length of steel wire that can hang vertically without breaking. ρρ is the density of steel and AA is the cross-sectional area of steel wire.
∴∴ Maximum stress, p=AlρgA=lρgp = \dfrac{Alρg}{A} = lρg

∴l=pρg∴ l = \dfrac{p}{ρg}

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