The position x of a particle varies with time ( t ) as x = A t ²- B t ³ . The acceleration at time t of the particle will be equal to zero. What is the value of t ?

Step-by-step solution

Given that x=A t²-B t³ velocity = dx dt =2 ~A t -3 ~B t ² and acceleration = d dt ( dx dt )=2 ~A -6 Bt For acceleration to be zero 2 ~A -6 Bt =0 . t = 2 ~A 6 ~B = A 3 ~B