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BITSAT2024PhysicsMotion in Two DimensionsActual

The range of the projectile projected at an angle of 15^ with horizontal is 50 m . If the projectile is projected with same velocity at an angle of 45^ with horizontal, then its range will be :

Options

  1. A50 m
  2. B50 2 ~m
  3. C100 m
  4. D100 2 ~m

Correct answer

C. 100 m

Step-by-step solution

Range of projectile R= v^2 2 g ( R (2 )) R₁ R₂ = (2 ₁ ) (2 ₂ ) = (2 15) (2 45) = 30^ 90^ 50 R ₂ = 1 2 R ₂=100 ~m

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