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BITSAT 2024Paper 2
Exam
BITSAT
Year
2024
Paper
Paper 2
Subject
Physics
Chapter
Motion in Two Dimensions

BITSAT 2024 · Paper 2 · Physics · Motion in Two Dimensions

A particle of mass m is projected with a velocity ' u ' making an...

A particle of mass mm is projected with a velocity ' uu ' making an angle of 30∘30^{{}^{\circ}} with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height hh is:

Options

  1. A316mu3g\frac{\sqrt{3}}{16} \frac{\mathrm{mu}^3}{\mathrm{ g}}
  2. B32mu2g\frac{\sqrt{3}}{2} \frac{\mathrm{mu}^2}{\mathrm{ g}}
  3. Cmu32g\frac{\mathrm{mu}^3}{\sqrt{2} \mathrm{ g}}
  4. Dzero

Correct answer

A. 316mu3g\frac{\sqrt{3}}{16} \frac{\mathrm{mu}^3}{\mathrm{ g}}

Step-by-step solution

Angular momentum, L=mvH=mucos⁡30H=mucos⁡30∘×u2sin⁡2θ2g[∵H=u2sin⁡2θ2g]=mu32g×32×(12)2=3mu316gL=m v H=m u \cos 30 H=m u \cos 30^{{}^{\circ}} \times \frac{u^2 \sin ^2 \theta}{2 g}\left[\because H=\frac{u^2 \sin ^2 \theta}{2 g}\right]=\frac{m u^3}{2 g} \times \frac{\sqrt{3}}{2} \times\left(\frac{1}{2}\right)^2=\frac{\sqrt{3} m u^3}{16 g}
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